JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    A rocket is fired vertically from the earth with an acceleration of 2g, where g is the gravitational acceleration. On an inclined plane inside the rocket, making an angle\[\theta \]. With the horizontal, a point object of mass m is kept. The minimum coefficient of friction \[{{\mu }_{\min }}\] between the mass and the inclined surface such that he mass does not move is:                 [JEE ONLINE 09-04-2016]

    A) \[\tan \theta \]

    B) \[\tan 2\theta \]

    C) \[3\tan \theta \]

    D) \[2\tan \theta \]

    Correct Answer: A

    Solution :

    [a] \[{{g}_{eft}}=3g\,\text{but}\,{{\mu }_{\min }}|=\tan \theta \]

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