JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    An automobile, travelling at \[40km/h\], can be stopped at a distance of \[40m\]by applying brakes. If the same automobile is travelling at \[80km/h\], the minimum stopping distance, in metres, is (assume no skidding) [JEE Online 15-04-2018]

    A) \[75m\]

    B) \[160m\]

    C) \[100m\]

    D) \[150m\]

    Correct Answer: B

    Solution :

    [b] Since stopping distance,
    For case \[1,40=\frac{{{(40\times \frac{5}{18})}^{2}}}{2a}..........(1)\]
    For case 2, \[s=\frac{{{(80\times \frac{5}{18})}^{2}}}{2a}...........(2)\]
    From (1) and (2), \[s=160m\]

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