A) \[75m\]
B) \[160m\]
C) \[100m\]
D) \[150m\]
Correct Answer: B
Solution :
| [b] Since stopping distance, |
| \[s=\frac{{{v}^{2}}}{2a}\] |
| For case \[1,40=\frac{{{(40\times \frac{5}{18})}^{2}}}{2a}..........(1)\] |
| For case 2, \[s=\frac{{{(80\times \frac{5}{18})}^{2}}}{2a}...........(2)\] |
| From (1) and (2), \[s=160m\] |
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