• # question_answer Two blocks A and B of masses ${{m}_{A}}=1kg$and ${{m}_{B}}=3kg$are kept on the table as shown in figure. The coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2. The maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is : (Take $g=10\text{ }m/{{s}^{2}}$) [JEE Main 10-4-2019 Afternoon] A) 16 N B) 40 N C) 12 N D) 8 N

 [a] ${{a}_{A\max }}=\mu g=2m/{{s}^{2}}$ $F-8=4\times 2$ $F=16N$