JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    Three forces start acting C simultaneously   on a particle   moving   with velocity v. These forces are    represented in magnitude and direction by the three sides of a \[\Delta ABC\] (as shown). The particle will now move with velocity
     [AIEEE 2003]

    A) less than v

    B) greater than v  

    C) \[\left| v \right|\] in the direction of largest force BC

    D) v remain unchanged

    Correct Answer: D

    Solution :

    [d] Resultant force is zero, as three forces acting on the particle can be represented in magnitude and direction by three sides of a triangle in same order. Hence, by Newton's 2nd law \[\left( F=m\frac{d\,\,v}{dt} \right)\], particle velocity (v) will be same. (\[\because \] if F = 0, v = constant)

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