• # question_answer Three forces start acting C simultaneously   on a particle   moving   with velocity v. These forces are    represented in magnitude and direction by the three sides of a $\Delta ABC$ (as shown). The particle will now move with velocity  [AIEEE 2003] A) less than v B) greater than v   C) $\left| v \right|$ in the direction of largest force BC D) v remain unchanged

Correct Answer: D

Solution :

 [d] Resultant force is zero, as three forces acting on the particle can be represented in magnitude and direction by three sides of a triangle in same order. Hence, by Newton's 2nd law $\left( F=m\frac{d\,\,v}{dt} \right)$, particle velocity (v) will be same. ($\because$ if F = 0, v = constant)

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