watt. The mass of the fuel consumed per hour in the reactor will be: (velocity of light, c is 
) [JEE Online 09-04-2017]
A)
B)
C)
D)
Correct Answer: C
Solution :
| [c] \[P=\frac{E}{\Delta t}\,=\frac{\Delta m{{c}^{2}}}{\Delta t}\] |
| \[\frac{\Delta m}{\Delta t}=\frac{P}{{{c}^{2}}}\,=\frac{{{10}^{9}}}{{{(3\times {{10}^{8}})}^{2}}}=4\times {{10}^{-2}}\,gm\] |
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