question_answer

A nucleus with \[Z=92\] emits the following in a sequence: \[\alpha ,\alpha ,{{\beta }^{-}},{{\beta }^{-}},\alpha ,\alpha ,\alpha ,\alpha ;{{\beta }^{-}},{{\beta }^{-}},\alpha ,{{\beta }^{+}},{{\beta }^{+}},\alpha \]. The Z of the resulting nucleus is    [AIEEE 2003]

A) 76

B) 78

C) 82

D) 74       

Correct Answer: B

Solution :

[b] Since, 8 -particles,  -particles and  -particles are emitted, so new atomic number