JEE Main & Advanced Physics Nuclear Physics And Radioactivity JEE PYQ-Nuclear Physics

  • question_answer
    The binding energy per nucleon of deuteron\[(_{1}^{2}H)\]and helium nucleus\[(_{2}^{4}He)\]is,\[1.1\,MeV\]and \[7\text{ }MeV,\]respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is          [AIEEE 2004]

    A) \[13.9\text{ }MeV\]

    B) \[26.9\text{ }MeV\]

    C) \[23.6\text{ }MeV\]

    D) \[19.2\text{ }MeV\]

    Correct Answer: C

    Solution :

    [c] As givenenergy
    The binding energy per nucleon of a deuteron
    Total binding energy of one deuteron nucleus
    The binding energy per nucleon of helium
     Total binding energy
    Hence, energy released in the above process


You need to login to perform this action.
You will be redirected in 3 sec spinner