question_answer

A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at\[2m/{{s}^{2}}\]. He peaches the ground with a speed of 3 m/s. At what height, did he bail out? [AIEEE 2005]

A) 91 m

B) 182m

C) 293m

D) 111 m

Correct Answer: C

Solution :

[c] Parachute bails out at height H from ground velocity at A

The velocity at ground         (given)

Acceleration       (given)

\[H=242.75+h=242.75+50\approx 293\,m\]