A) 12m
B) 18m
C) 24m
D) 6m
Correct Answer: C
Solution :
| [c] From equation of motion, \[{{v}^{2}}={{u}^{2}}+2as,\]. |
| we get \[0={{\left( 50\times \frac{5}{18} \right)}^{2}}+2\,a\times 6\] |
| \[a=-16\,m/{{s}^{2}}\](here, a = retardation) |
| Again \[{{v}^{2}}={{u}^{2}}+2\,as\] |
| \[0-{{\left( 100\times \frac{5}{18} \right)}^{2}}-16\times 2\times s\] |
| \[s=\frac{{{(100\times 5)}^{2}}}{18\times 18\times 32}=24.1\approx 24\,m\] |
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