| A thin convex lens L (refractive index = 1.5) is placed on a plane mirror M. When a pin is |
| placed at A, such that OA = 18 cm, its real inverted image is formed at A itself, as shown in figure. When a liquid of refractive index \[{{\mu }_{1}}\] is put between the lens and the mirror, The pin has to be moved to A', such that OA' = 27 cm, to get its inverted real image at A' itself. The value of μ1 will be :- [JEE Main 9-4-2019 Afternoon] |
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A) \[\sqrt{2}\]
B) \[\frac{4}{3}\]
C) \[\sqrt{3}\]
D) \[\frac{3}{2}\]
Correct Answer: B
Solution :
[b]  |
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when is filled between lens and mirror |
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