question_answer

Three particles of masses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1 m (as shown in the figure). The (x, y) coordinates of the centre of mass will be : [JEE Main 12-4-2019 Afternoon]

A)  \[\left( \frac{7}{12}m,\frac{\sqrt{3}}{8}m \right)\]           

B)  \[\left( \frac{\sqrt{3}}{4}m,\frac{5}{12}m \right)\]

C)  \[\left( \frac{7}{12}m,\frac{\sqrt{3}}{4}m \right)\]           

D)       \[\left( \frac{\sqrt{3}}{8}m,\frac{7}{12}m \right)\]           

Correct Answer: C

Solution :

[c]

The co-ordinates of the centre of mass

Co-ordinate