A circular hole of radius \[\frac{R}{4}\] is made in a thin uniform disc having mass M and radius R, as shown in figure. The moment of inertia of the remaining portion of the disc about an axis passing through the point \[\text{O}\] and perpendicular to the plane of the disc is [JEE Online 09-04-2017] |
A) \[\frac{219{{R}^{2}}}{256}\,\]
B) \[\frac{237M{{R}^{2}}}{512}\]
C) \[\frac{197M{{R}^{2}}}{256}\,\]
D) \[\frac{19M{{R}^{2}}}{512}\]
Correct Answer: B
Solution :
[b] |
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