| Two identical capacitors A and B, charged to the same potential 5V are connected in two different circuits as shown below at time t = 0. If the charge on capacitors A and B at time t = CR is \[{{Q}_{A}}\] and \[{{Q}_{B}}\] respectively, then (Here e is the base of natural logarithm) [JEE MAIN Held on 09-01-2020 Evening] |
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A) \[{{Q}_{A}}=\frac{CV}{2},{{Q}_{B}}=\frac{VC}{e}\]
B) \[{{Q}_{A}}=VC,{{Q}_{B}}=CV\]
C) \[{{Q}_{A}}=\frac{CV}{e},{{Q}_{B}}=\frac{VC}{2}\]
D) \[{{Q}_{A}}=VC,{{Q}_{B}}=\frac{VC}{e}\]
Correct Answer: D
Solution :
| [d] In case I diode is reverse biased |
| \[{{Q}_{A}}\text{ }=\text{ }CV\] |
| n case II, current will flow as diode is forward biased. |
| \[{{Q}_{B}}=\frac{CV}{e}\] |
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