Two simple pendulums of length 1m and 4mrespectively are both given small d is placement in the same direction at the same instant. They will be again in phase after the shorter pendulum has completed number of oscillations equal to: [JEE ONLINE 09-04-2013]
A) 2
B) 7
C) 5
D) 3
Correct Answer:
A
Solution :
[a] Let and be the time period of shorter length and larger length pendulums respectively. According to question,