question_answer

If the time period \[t\] of the oscillation of a drop of liquid of density \[d\]radius \[r,\]vibrating under surface tension s is given by the formula \[t=\sqrt{{{r}^{2b}}{{s}^{c}}{{d}^{a/2}}.}\] It is observe that the time period is directly proportional to \[\sqrt{\frac{d}{s}.}\] The value of \[b\] should therefore be:                         [JEE ONLINE 23-04-2013]

A)        \[\frac{3}{4}\]             

B)       \[\sqrt{3}\]

C)  \[\frac{3}{2}\] 

D)       \[\frac{2}{3}\]