JEE Main & Advanced Physics Simple Harmonic Motion JEE PYQ-Simple Harmonic Motion

  • question_answer
    Two particles A and B of equal masses are suspended from two massless springs of spring constants \[{{k}_{1}}\] and \[{{k}_{2}}\], respectively. If the   maximum   velocities,   during oscillations are equal, the ratio of amplitudes of A and B is            [AIEEE 2003]

    A)  \[\sqrt{{{k}_{1}}/{{k}_{2}}}\]         

    B)       \[{{k}_{1}}/{{k}_{2}}\]

    C)  \[\sqrt{{{k}_{2}}/{{k}_{1}}}\]  

    D)       \[{{k}_{2}}/{{k}_{1}}\] \[\]

    Correct Answer: C

    Solution :

    [c] The maximum velocity,
               
    where, A is amplitude and T is time period.
    Hence, 
                              (given)
               


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