question_answer

Two particles are performing simple harmonic motion in a straight line about the same equilibrium point.

The amplitude and time period for both particles are same and equal to A and T, respectively. At time t = 0 one particle has displacement A while the other one has displacement \[\frac{-A}{2}\]and they are moving towards each other .If they cross each at time t, then t is:                                                                          [JEE ONLINE 09-04-2016]

A) \[\frac{T}{4}\]              

B)      \[\frac{5T}{6}\]

C) \[\frac{T}{3}\]              

D)      \[\frac{T}{6}\]

Correct Answer: D

Solution :

[d]