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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion JEE PYQ-Thermometry Calorimetry and Thermal Expansion

  • question_answer
    500 g of water and 100 g of ice at \[{{0}^{0}}\operatorname{C}\]are in a calorimeter whose water equivalent is \[40g.\] \[10\,g\] of steam at \[{{100}^{0}}C\] is added to it Then water in the calorimeter is: [JEE ONLINE 23-04-2013] (Latent heat of ice = 80 cal/g, Latent heat of stem = 540 cal/g)                              

    A)        580 g  

    B)       590 g

    C)  600 g

    D)                   610 g

    Correct Answer: B

    Solution :

    [b] As 1g of steam at 100°C melts 8g of ice at 0°C.
    10 g of steam will melt 8x 10 g of ice at 0°C Water in calorimeter = 500 + 80 + 10g = 590g


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