A) zero
B) (b)\[\frac{m{{\upsilon }^{3}}}{\sqrt{2}g}\]
C) (c)\[\frac{\sqrt{3}}{16}\frac{m{{\upsilon }^{3}}}{g}\]
D) (d)\[\frac{\sqrt{3}}{2}\frac{m{{\upsilon }^{2}}}{g}\]
Correct Answer: C
Solution :
[c] |
\[{{L}_{0}}={{\Pr }_{\bot }}\] |
\[{{L}_{0}}=mv\cos \theta H\] |
\[=mg\frac{\sqrt{3}}{2}.\frac{{{v}^{2}}{{\sin }^{2}}{{30}^{o}}}{2g}=\frac{\sqrt{3}m{{v}^{3}}}{16g}.\] |
You need to login to perform this action.
You will be redirected in
3 sec