JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति JEE PYQ - Work Energy Power and Collision

  • question_answer
    A block of mass 0.50 kg is moving with a speed of 2.00 \[m{{s}^{-1}}\] on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is [AIEEE 2008]

    A) 0.67 J

    B) 0.34 J

    C) 0.16 J

    D) 1.00 J

    Correct Answer: A

    Solution :

    [a] Using momentum conservation,
    \[0.5\times 2=1.5\times v\Rightarrow v=\frac{2}{3}m{{s}^{-1}}\]
    Loss of energy
    \[\left[ \left( \frac{1}{2}\times 0.5\times {{\left( 2 \right)}^{2}} \right)-\frac{1}{2}\times 1.5\times {{\left( \frac{2}{3} \right)}^{2}} \right]=1-\frac{1}{3}\]
    = 2 0.67 J


You need to login to perform this action.
You will be redirected in 3 sec spinner