A) constant
B) t
C) \[\frac{1}{\sqrt{t}}\]
D) \[\sqrt{t}\]
Correct Answer: C
Solution :
| [c] K.E. = ct |
| \[\frac{1}{2}m{{v}^{2}}=ct\] |
| \[\frac{{{P}^{2}}}{2m}=ct\] |
| \[P=\sqrt{2ctm}\] |
| \[F=\frac{dP}{dt}=\sqrt{2cm}\frac{1}{2}\times \frac{1}{\sqrt{t}}\] |
| \[F\propto \frac{1}{\sqrt{t}}.\] |
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