A) 0.80
B) 0.94
C) 0.85
D) 0.74
Correct Answer: C
Solution :
| [c] The phase difference between two waves is given as\[\Delta x\times \frac{2\pi }{\lambda }=\frac{\lambda }{8}\times \frac{2\pi }{\lambda }=\frac{\pi }{4}\] |
| So, the intensity at this point is |
| \[I={{I}_{0}}{{\cos }^{2}}\frac{\pi }{8}\] |
| \[I={{I}_{0}}\left( \frac{1+\cos \frac{\pi }{4}}{2} \right)\] |
| \[I={{I}_{0}}\left( \frac{1+\frac{1}{\sqrt{2}}}{2} \right)=0.85{{I}_{0}}\] |
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