A) \[t=k{{\rho }^{1/2}}\]
B) \[t=k\rho \]
C) \[t=k{{\rho }^{-1}}\]
D) \[t=k{{\rho }^{-1/2}}\]
Correct Answer: D
Solution :
Time period of satellite is given by \[t=2\pi \sqrt{\frac{{{R}^{3}}}{GM}}=2\pi \sqrt{\frac{{{R}^{3}}}{G\left( \frac{4}{3} \right)\pi {{R}^{3}}\rho }}\] \[\Rightarrow \] \[t\propto \frac{1}{\sqrt{\rho }}\]You need to login to perform this action.
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