A) resistivity
B) resistance
C) potential difference
D) electric field
Correct Answer: B
Solution :
We know that \[M{{L}^{2}}{{T}^{-3}}\] is the dimension of power, hence the given quantity is \[=\frac{\text{power}}{{{\text{(current)}}^{\text{2}}}}\] We also know that \[{{i}^{2}}R=power\] So, \[R=\frac{\text{power}}{{{\text{(current)}}^{\text{2}}}}\] Therefore, \[M{{L}^{2}}{{T}^{-3}}{{I}^{-2}}\] is the dimension of resistance.You need to login to perform this action.
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