A) an acid
B) a \[\]-hydroxy aldehyde
C) a \[\]-hydroxy ketone
D) an alcohol
Correct Answer: B
Solution :
In the presence of dilute base or dilute acid, two molecules of an aldehyde or ketone, condense to form \[\beta \]-hydroxy aldehyde or \[\beta \]-hydroxy ketone respectively. This reaction is called Aldol condensation. \[\underset{\text{Acetaldehyde}\,\,\text{(2}\,\text{molecules)}}{\mathop{C{{H}_{3}}--\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,==O+H.C{{H}_{2}}--\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,--H\xrightarrow{dil.\,NaOH}}}\,\] \[\underset{\text{Aldol}}{\mathop{C{{H}_{3}}--\underset{OH}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,--C{{H}_{2}}}}\,--CHO\]
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