A) \[{{C}_{2}}{{H}_{5}}Br+{{(C{{H}_{3}})}_{3}}CONa\]
B) \[{{C}_{2}}{{H}_{5}}Br+{{C}_{2}}{{H}_{5}}ONa\]
C) \[{{C}_{6}}{{H}_{5}}Br+{{C}_{3}}{{H}_{7}}ONa\]
D) \[{{C}_{2}}{{H}_{5}}Br+{{C}_{6}}{{H}_{5}}ONa\]
Correct Answer: C
Solution :
Alkyl halides gives ether, on treating with strong base (\[{{C}_{2}}{{H}_{5}}ONa\] etc.). This is called Willamsons synthesis of ethers. Aryl halides does not give this reaction due to less reactivity for nucleophilic substitution.
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