question_answer

If the same volume of two liquids of densities \[{{d}_{1}}\]and \[{{d}_{2}}\] flow in times \[{{t}_{1}}\] and \[{{t}_{2}}\] through the same capillary tube the ratio of their coefficients of viscosity is given by:

A)  \[\frac{{{d}_{1}}{{d}_{2}}}{{{t}_{1}}{{t}_{2}}}\]                                  

B) \[\frac{{{d}_{1}}{{d}_{2}}}{{{t}_{2}}{{t}_{1}}}\]                   

C) \[\frac{{{d}_{1}}{{d}_{1}}}{{{t}_{2}}{{t}_{2}}}\]                   

D)        \[\frac{{{t}_{1}}}{{{t}_{2}}}\]