A) \[{{K}_{4}}[Fe{{(CN)}_{6}}]\]
B) \[[Cu{{(N{{H}_{3}})}_{5}}Cl]\]
C) \[{{[NiC{{l}_{4}}]}^{2-}}\]
D) all of these
Correct Answer: C
Solution :
\[{{[NiC{{l}_{4}}]}^{2-}}\]has paramagnetic behaviour as it contains 2 unpaired electrons.
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