A) \[sp\] and \[s{{p}^{2}}\text{-}\]hybridised C-atoms
B) \[sp\] \[s{{p}^{2}}\] and \[s{{p}^{3}}\text{-}\]hybridised C-atoms
C) only \[s{{p}^{2}}\text{-}\] hybridised C-atoms
D) only \[sp\]- hybridised C-atoms
Correct Answer: C
Solution :
\[\underset{1,\,\,\text{3-butadiene}}{\mathop{{{H}_{2}}C==\,CH--HC==C{{H}_{2}}}}\,\] In this compound each carbon is \[s{{p}^{2-}}\] hybridised, (as each carbon has one double borid).
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