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JIPMER Jipmer Medical Solved Paper-2000

  • question_answer
    110 J of heat are added to a gaseous system whose internal energy is 40 J, then the amount of external work done is:

    A)  40 J                                       

    B)         110 J                    

    C)         70 J                                       

    D)         150 J

    Correct Answer: C

    Solution :

    From the thermodynamic relation \[\Delta Q=\Delta U+\Delta W\]               ?(i) Given   \[\Delta Q=110\,J,\] \[\Delta U=40\,J\] From equation (i), we get so,          \[110J=40J+\Delta W\] \[\Delta W=110-40=70J\]


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