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JIPMER Jipmer Medical Solved Paper-2000

  • question_answer
    A man fires a bullet of mass 200 g at a speed of 5 m/s. The gun is of one kg mass. By what velocity the gun rebounds backwards:

    A)  0.01 m/s                             

    B)         1 m/s                   

    C)         10 m/s                                

    D)         0.1 m/s

    Correct Answer: B

    Solution :

    Applying the law of conservation of momentum \[m\times \upsilon =m\times \upsilon \] where m = mass of bullet = 200 g \[m\]= mass of gun = 1 kg velocity of bullet \[=v=5\,\,m\text{/}s\] \[\therefore \]  \[\frac{200}{1000}\times 5=1\times v\] Hence   \[\upsilon =1\,m\text{/}s\]


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