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JIPMER Jipmer Medical Solved Paper-2000

  • question_answer
    A spring 40 mm long is stretched by the application of a force. If 10 N force is required to stretch the spring through 1 mm, then work done in stretching the spring through 40 mm is:

    A)  8 J                                         

    B)         23 J                       

    C)         68 J                                       

    D)         84 J

    Correct Answer: A

    Solution :

    From the relation \[F=kx\] or            \[k=\frac{F}{x}=\frac{10}{1\times {{10}^{-3}}}={{10}^{4}}N\text{/}m\] and also \[F=kx={{10}^{4}}\times 40\times {{10}^{-3}}=400\,N\] Now work done, \[W=\frac{1}{2}Fx=\frac{1}{2}\times 400\times 40\times {{10}^{-3}}=8\,J\]


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