A) 1
B) \[1.11\times {{10}^{-10}}\]
C) \[1.12\times {{10}^{4}}\]
D) \[1.1\times {{10}^{19}}\]
Correct Answer: C
Solution :
We know that the number of lines of force coming out from a unit charge in C.G.S. system is \[4\pi \] and in S.I. system is \[\frac{1}{{{\varepsilon }_{0}}}.\] Where value of\[{{\varepsilon }_{0}}=8.85\times {{10}^{-12}}\] Therefore \[\frac{1}{{{\varepsilon }_{0}}}=\frac{1}{8.85\times {{10}^{-12}}}\] \[=\frac{{{10}^{12}}}{8.85}=1.12\times {{10}^{11}}\]
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