A) \[HN{{O}_{3}}+LiOH\]
B) \[HCOOH+KOH\]
C) \[HCl+N{{H}_{4}}OH\]
D) \[C{{H}_{3}}COOH+NaOH\]
Correct Answer: A
Solution :
Heat of neutralisation is the heat evolved, when an acid reacts with a base. The value of heat of neutralisation of a strong acid and a strong base is always found to be constant and is equal to 57.3 kJ/mol. Here \[HN{{O}_{3}}\] is a strong acid and \[LiOH\] a strong base, hence their heat of neutralisation will be equal to 57.3 kJ/mol.
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