A) \[50{}^\circ C\]
B) \[473{}^\circ C\]
C) \[446{}^\circ C\]
D) \[200{}^\circ C\]
Correct Answer: B
Solution :
Given that, \[{{V}_{1}}=100\,ml,\] \[{{T}_{1}}=273+100=373\,K\] \[{{V}_{2}}=200ml,\text{ }{{T}_{2}}=?\] From Charles law: \[\frac{{{V}_{1}}}{{{T}_{1}}}=\frac{{{V}_{2}}}{{{T}_{2}}}\] (at constant P) or \[{{T}_{2}}=\frac{{{V}_{2}}\cdot {{T}_{1}}}{{{V}_{1}}}=\frac{200\times 373}{100}\] \[=746\,K=746-273=473{}^\circ C\]
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