question_answer

When acetone reacts with bleaching powder, the compound formed is:

A)  \[C{{H}_{3}}COOH\]      

B)         \[C{{H}_{3}}CHO\]         

C)         \[CHC{{l}_{3}}\]              

D)         \[CC{{l}_{4}}\]

Correct Answer: C

Solution :

Acetone reacts with bleaching powder to form chloroform. The reaction is in three steps as follows: (i) \[\underset{\begin{smallmatrix}  Bleaching \\  \,\,powder \end{smallmatrix}}{\mathop{CaOC{{l}_{2}}}}\,+{{H}_{2}}O\xrightarrow{{}}Ca{{(OH)}_{2}}+C{{l}_{2}}\] (ii) \[\underset{Acetone}{\mathop{C{{H}_{3}}COC{{H}_{3}}}}\,+3C{{l}_{2}}\xrightarrow{{}}\] \[\underset{\text{Trichloroacetone}}{\mathop{CC{{l}_{3}}COC{{H}_{3}}+3HCl}}\,\,\] (iii)