A) \[HSO_{3}^{-}\]
B) \[B{{F}_{3}}\]
C) Ammonia
D) \[O{{H}^{-}}\]
Correct Answer: B
Solution :
\[B{{F}_{3}}\] is not a nucleophile. It is an electrophile as it is deficient of electrons. \[F:\overset{F}{\mathop{\overset{.\,\,\,.}{\mathop{B}}\,}}\,:F\](octet of B is not complete)
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