JIPMER Jipmer Medical Solved Paper-2001

  • question_answer
    The escape velocity from the surface of earth is \[{{\upsilon }_{es.}}\] The escape velocity from the surface of a planet whose mass and radius are 3 times those of the earth will be:

    A)  \[3{{\upsilon }_{es}}\]     

    B)                                         \[9{{\upsilon }_{es}}\]                 

    C)  \[{{\upsilon }_{es}}\]                    

    D)         \[27{{\upsilon }_{es}}\]

    Correct Answer: C

    Solution :

    The relation for escape velocity is given by \[{{v}_{es(e)}}=\sqrt{\frac{2G{{M}_{e}}}{{{R}_{e}}}}\] \[{{v}_{es(p)}}=\sqrt{\frac{2G\times 3{{M}_{e}}}{3{{R}_{e}}}}={{v}_{es(e)}}\]


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