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JIPMER Jipmer Medical Solved Paper-2001

  • question_answer
    The internal resistance of a primary cell is 4 \[\Omega \] It generates a current of 0.2 amp in an external resistance of 21 \[\Omega \] The rate at which chemical energy to consumed in providing current is:

    A)  1 J/s   

    B)                                         5 J/s                     

    C)  0.42 J/s               

    D)         0.8 J/s

    Correct Answer: A

    Solution :

    Rate of energy\[\frac{H}{t}={{i}^{2}}R\] (But total\[R=21+4=25\,\Omega \]) so           \[\frac{H}{t}=0.2\times 0.2\times 25=1\,J\text{/}s\]


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