A) \[NH_{4}^{+}\]
B) \[N{{H}_{3}}\]
C) any species that will form\[NH_{4}^{+}\]
D) all the above
Correct Answer: A
Solution :
\[N{{H}_{3}}+N{{H}_{3}}\,\,\,\,\rightleftharpoons \underset{\begin{smallmatrix} \text{proton}\,\text{donar} \\ \,\,\,\,\,\,\,\,\,\,\text{(acid)} \end{smallmatrix}}{\mathop{NH_{4}^{+}}}\,+NH_{2}^{-}\] Hence, \[NH_{4}^{+}\] can donate proton and is an acid.
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