A) \[2\times {{10}^{-6}}\text{g/hr}\]
B) \[9\times {{10}^{-12}}\text{g/hr}\]
C) \[8\times {{10}^{-9}}\text{g/hr}\]
D) \[2\times {{10}^{-9}}\text{g/hr}\]
Correct Answer: D
Solution :
As fuel consumed by the react or with efficiency 20%. Then energy will be: \[E=\frac{100\times 10}{20}=50\,J\text{/}s\] As \[E=m{{c}^{2}},\] \[m=\frac{E}{{{c}^{2}}}\] \[=\frac{50}{{{(3\times {{10}^{8}})}^{2}}}kg\text{/}\sec \] \[=\frac{50\times 3600\times {{10}^{3}}}{{{(3\times {{10}^{8}})}^{2}}}g\text{/}hr\] \[=2\times {{10}^{-9}}g\text{/}hr\]
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