JIPMER Jipmer Medical Solved Paper-2002

  • question_answer
    A particle of mass 4 kg is acted upon by steady force of 4 N distance travelled by the particle in 4 sec is:

    A)  10m                                     

    B)  2m                        

    C)         4m                        

    D)         8 m

    Correct Answer: D

    Solution :

    \[F=ma\]  or  \[a=\frac{F}{m}=\frac{4N}{4kg}=1\,m\text{/}{{s}^{2}}\] \[s=ut+\frac{1}{2}a{{t}^{2}}\]    (since \[u=0,\]\[t=4\sec \]) \[s=\frac{1}{2}\times 1\times {{4}^{2}}=8\,m\]


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