A) \[2\sqrt{2}\times {{10}^{-6}}\text{Nm}\]
B) \[8\times {{10}^{8}}\text{Nm}\]
C) \[4\times {{10}^{-}}^{7}\text{Nm}\]
D) \[4\times {{10}^{-}}^{9}\text{Nm}\]
Correct Answer: C
Solution :
\[\tau =\overrightarrow{p}\times \overrightarrow{E}=pE\sin \theta \] \[{{\tau }_{\max }}=p\times E\] (As \[\theta =90{}^\circ ,\] \[p=ql\]) \[=ql\times E=2\times {{10}^{-10}}\times 1\times {{10}^{-2}}\times 2\times {{10}^{5}}\] \[=4\times {{10}^{-7}}Nm\]
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