A) - 1.5 D
B) - 6.5 D
C) 46.6 D
D) 6.6 D
Correct Answer: A
Solution :
Power \[P=\frac{1}{{{f}_{1}}}+\frac{1}{{{f}_{2}}}\] Here: \[{{f}_{1}}=140\,cm\] \[=1.4\,m\] \[=\frac{1}{0.40}+\frac{1}{-\,0.25}\] \[{{f}_{2}}=-\,25\,m\] \[=-1.5\,D\] \[=-\,0.25\,cm\]
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