A) \[11.2\text{ }m\text{/}s\]
B) \[112\text{ }m\text{/}s\]
C) \[\frac{0.64\times 20}{1000\times 100}\text{m/s}\]
D) \[\frac{1000}{64\times 20}\text{m/s}\]
Correct Answer: A
Solution :
\[{{\upsilon }_{\max }}=\sqrt{\mu rg}=\sqrt{0.64\times 20\times 9.8}\] \[=11.2\,\,m\text{/}s\]
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