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JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    A capillary tube of radius r can support a liquid of weight\[6.28\times {{10}^{-4}}\text{N}\text{.}\] if the surface tension of the liquid is \[5\times {{10}^{-2}}\] N/m. The radius of capillary must be:

    A)  \[2.0\times {{10}^{-3}}\text{m}\]           

    B)         \[2.0\times {{10}^{-4}}\text{m}\]           

    C)  \[1.5\times {{10}^{-3}}\text{m}\]      

    D)         \[12.5\times {{10}^{-4}}\text{m}\]

    Correct Answer: A

    Solution :

    \[W=T.\,2\pi r\] \[r=\frac{W}{2\pi T}=\frac{6.28\times {{10}^{-4}}}{2\times 3.14\times 5\times {{10}^{-2}}}\]  \[=2\times {{10}^{-3}}m\]


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