A) 3.6
B) \[3.6\times {{10}^{-4}}\]
C) \[3.6\times {{10}^{-11}}\]
D) \[3.6\times {{10}^{-6}}\]
Correct Answer: B
Solution :
Velocity of wave is given by \[\upsilon =\frac{\omega }{k}=\frac{1800}{6}=300\,m\text{/}s\] Maximum particle velocity is \[{{u}_{\max }}=A\omega =60\times {{10}^{-6}}\times 1800\,m\text{/}s\] The ratio is \[\frac{{{u}_{\max }}}{\upsilon }=\frac{60\times {{10}^{-6}}\times 1800}{300}=3.6\times {{10}^{-4}}\]
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