A) \[15{}^\circ \]
B) \[30{}^\circ \]
C) \[60{}^\circ \]
D) \[45{}^\circ \]
Correct Answer: D
Solution :
Speed of particle \[\upsilon =\frac{s}{t}=\frac{34.3}{\sqrt{22}}m\text{/}s\] \[r=\frac{s}{2\pi }=\frac{34.3}{2\pi }m\] Now, \[\tan \theta =\frac{{{\upsilon }^{2}}}{rg}=\frac{\frac{{{(34.3)}^{2}}}{22}}{\frac{34.3}{2\pi }\times 9.8}=1\] \[=45{}^\circ \]
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