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JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    The radius of earth is 6400 km and\[g=10\text{ }m\text{/}{{s}^{2}}\]. In order that a body of 5 kg weight is zero at the equator, the angular speed is:

    A)  \[\frac{1}{800}\text{rad/sec}\]                

    B)  \[\frac{1}{1600}\text{rad/sec}\]              

    C)         \[\frac{1}{400}\text{rad/sec}\]    

    D)         \[\frac{1}{80}\text{rad/sec}\]

    Correct Answer: A

    Solution :

    \[g=0\]and\[g=R{{\omega }^{2}}\] \[\omega =\sqrt{\frac{g}{R}}=\sqrt{\frac{10}{6400\times {{10}^{3}}}}\] \[=\frac{1}{800}rad\text{/}\sec \]


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