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JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    If the energy released in the fission of one nucleus is \[3.2\times {{10}^{-11}}\text{J,}\] then number of nuclei required per second in a power plant of 16 kW is:

    A)  \[0.5\,\times {{10}^{14}}\]        

    B)         \[0.5\times {{10}^{12}}\]            

    C)         \[5\times {{10}^{12}}\]                

    D)         \[5\times {{10}^{14}}\]

    Correct Answer: D

    Solution :

    The number of nuclei required per second is \[n=\frac{P}{E}=\frac{16\times {{10}^{3}}}{3.2\times {{10}^{-11}}}=5\times {{10}^{14}}\]


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